Published September 10, 2022 by Tech Network

Bob at the Bank Java Solution (BOBBANK)

Problem

Bob has an account in the Bobby Bank. His current account balance is W rupees.
Each month, the office in which Bob works deposits a fixed amount of X rupees to his account.
Y rupees is deducted from Bob's account each month as bank charges.
Find his final account balance after Z months. Note that the account balance can be negative as well.

Input Format

The first line will contain TT, the number of test cases. Then the test cases follow.
Each test case consists of a single line of input, containing four integers W,X,Y, and Z — the initial amount, the amount deposited per month, the amount deducted per month, and the number of months.

Output Format

For each test case, output in a single line the final balance in Bob's account after Z months.

Constraints

$1 \leq T \leq 1000$
$1 \leq W,X,Y,Z \leq 10^4$

Input

3 100 11 1 10 999 25 36 9 2500 100 125 101

Output

200 900 -25

Explanation:

Test case $1$ : Bob's current account balance is $100$ . At the end of each month Bob gets Rs $11$ and pays Rs $1$ , thus gaining $10$ per month. Thus, at the end of $10$ months, Bob will have $100 + 10 \times 10 = 200$ .

Test case $2$ : Bob's current account balance is $999$ . At the end of each month Bob gets Rs $25$ and pays Rs $36$ , thus losing $11$ per month. Thus, at the end of $9$ months, Bob will have $999 - 11 \times 9 = 900$ .

Test case $3$ : Bob's current account balance is $2500$ . At the end of each month Bob gets Rs $100$ and pays Rs $125$ , thus losing $25$ per month. Thus, at the end of $101$ months, Bob will have $2500 - 25 \times 101 = -25$ .

/* package codechef; // don't place package name! / import java.util.; import java.lang.; import java.io.; /* Name of the class has to be "Main" only if the class is public. / class Codechef { public static void main (String[] args) throws java.lang.Exception { try { Scanner sc = new Scanner(System.in); int t= sc.nextInt(); while(t>=1 && t<=1000) { int w = sc.nextInt(); int x = sc.nextInt(); int y = sc.nextInt(); int z = sc.nextInt(); int Bal=0; if(w>=1 && w<=10000 && x>=1 && x<=10000 && y>=1 && y<=10000 && z>=1 && z<=10000) { Bal = w + ((x - y)z) ; System.out.println(Bal); } } } catch(Exception e) { return; } } }

Code

Published September 10, 2022 by Tech Network

Chef and Wire Frames Java Solution (CWIREFRAME)

Problem

Chef has a rectangular plate of length N cm and width M cm. He wants to make a wireframe around the plate. The wireframe costs X rupees per cm.

Determine the cost Chef needs to incur to buy the wireframe.

Input Format

First line will contain TT, the number of test cases. Then the test cases follow.

Each test case consists of a single line of input, containing three space-separated integers N,M,N,M, and XX — the length of the plate, width of the plate, and the cost of frame per cm.

Output Format

For each test case, output in a single line, the price Chef needs to pay for the wireframe.

Constraints

$1 \leq T \leq 1000$
$1 \leq N,M,X \leq 1000$

Explanation:

Test case $1$ : The total length of the frame is $2\cdot 10 + 2\cdot 10 = 40$ cms. Since the cost is $10$ per cm, the total cost would be $10 \cdot 40 = 400$ .

Test case $2$ : The total length of the frame is $2\cdot 23 + 2\cdot 3 = 52$ cms. Since the cost is $12$ per cm, the total cost would be $52 \cdot 12 = 624$ .

Test case $3$ : The total length of the frame is $2\cdot 1000 + 2\cdot 1000 = 4000$ cms. Since the cost is $1000$ per cm, the total cost would be $4000 \cdot 1000 = 4000000$ .

INPUT

3 10 10 10 23 3 12 1000 1000 1000

OUTPUT

400 624 4000000

 
 /* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
	public static void main (String[] args) throws java.lang.Exception
	{
    	try{
    		Scanner sc = new Scanner(System.in);
    		int t= sc.nextInt();
    		while(t>=1 && t<=1000)
    		{
    		    int n = sc.nextInt();
    		    int m = sc.nextInt();
    		    int x = sc.nextInt();
    		    int tlength = 0,cost=0;
    		    if(n>=1 && n<=1000 && m>=1 && m<=1000 && x>=1 && x<=1000)
    		    {
    		        tlength  = n * 2 + m * 2;
    		        cost = x * tlength;
    		        System.out.println(cost);
    		        
    		    }
    		}
    	}
    	catch(Exception e){
    	    return;
    	}
	}
}

Code

Published September 07, 2022 by Tech Network

Balls and Boxes Codechef Solution Java (BALLBOX)

Problem

You have NN balls and KK boxes. You want to divide the NN balls into KK boxes such that:
Each box contains ≥1 balls.
No two boxes contain the same number of balls.
Determine if it is possible to do so.

Input Format

The first line contains a single integer TT — the number of test cases. Then the test cases follow.
The first and only line of each test case contains two space-separated integers NN and KK — the number of balls and the number of boxes respectively.

Output Format

For each test case, output YES if it is possible to divide the NN balls into KK boxes such that the conditions are satisfied. Otherwise, output NO.
You may print each character of YES and NO in uppercase or lowercase (for example, yes, yEs, Yes will be considered identical).

Constraints

$1 \leq T \leq 1 0^{5}$
$1 \le N \le 10^9$
$1 \le K \le 10^4$

 
  
 /* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
	public static void main (String[] args) throws java.lang.Exception
	{
	    try{
        	   Scanner sc =new Scanner(System.in);
        	   int t= sc.nextInt();
        	   while(t>=1 && t<=100000)
        	   {
        	       
        	       int n  = sc.nextInt();
        	       int k = sc.nextInt();
        	       if(n>=1 && n<=(Math.pow(10, 9)) && k>=1 && k<=(Math.pow(10, 4)))
        	       {
        	           
        	           if(n==1 && k==1)
        	           {
        	               System.out.println("YES");
        	           }
        	           else{
        	           
        	               int val = k*(k+1)/2;
        	               if(n>=val)
        	               {
        	                   System.out.println("YES");
        	               }
        	               else
        	               {
        	                   System.out.println("NO");
        	               }
        	           }
        	           
        	           
        	       }
        	   }
	    }
	    catch(Exception e){
	        return;
	    }
	}
}

Code

Published September 07, 2022 by Tech Network

Broken Phone Codechef Solution Java: (BROKENPHONE)

Problem

Uttu broke his phone. He can get it repaired by spending XX rupees or he can buy a new phone by spending YY rupees. Uttu wants to spend as little money as possible. Find out if it is better to get the phone repaired or to buy a new phone.

Input Format

The first line contains a single integer TT — the number of test cases. Then the test cases follow.
The first and only line of each test case contains two space-separated integers XX and YY — the cost of getting the phone repaired and the cost of buying a new phone.

Output Format

For each test case,

output REPAIR if it is better to get the phone repaired.
output NEW PHONE if it is better to buy a new phone.
output ANY if both the options have the same price.

You may print each character of REPAIR, NEW PHONE and ANY in uppercase or lowercase (for example, any, ANy, Any will be considered identical).

Constraints

1<=T<=1000
1<=X,Y<=10000

 
  
 /* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
	public static void main (String[] args) throws java.lang.Exception
	{
        	try
        	{
        		Scanner sc = new Scanner(System.in);
        		int t = sc.nextInt();
        		while(t>=1 && t<=1000)
        		{
        		    int x= sc.nextInt();
        		    int y = sc.nextInt();
        		    
        		    if((x>=1 && x<=10000) && (y>=1 && y<=10000))
        		    {
        		        
        		        if(x>y)
        		        {
        		            System.out.println("NEW PHONE");
        		        }
        		        else if(x<y)
        		        {
        		            System.out.println("REPAIR");
        		        }else if(x==y)
        		        {
        		            System.out.println("ANY");
        		        }
        		        
        		    }
  
        		}
        	}
        	catch(Exception e){
        	    return;
        	}
	}
}

Code

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Bob at the Bank Java Solution (BOBBANK)

Problem

Input Format

Output Format

Constraints

Input

Explanation:

Chef and Wire Frames Java Solution (CWIREFRAME)

Problem

Input Format

Explanation:

Balls and Boxes Codechef Solution Java (BALLBOX)

Problem

Constraints

Broken Phone Codechef Solution Java: (BROKENPHONE)

Problem

Output Format

Constraints

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