Chef and Wire Frames Java Solution (CWIREFRAME)

Problem

• Chef has a rectangular plate of length N cm and width M cm. He wants to make a wireframe around the plate. The wireframe costs X rupees per cm.

• Determine the cost Chef needs to incur to buy the wireframe.

Input Format

• First line will contain TT, the number of test cases. Then the test cases follow.

Each test case consists of a single line of input, containing three space-separated integers N,M,N,M, and XX — the length of the plate, width of the plate, and the cost of frame per cm.

Output Format

For each test case, output in a single line, the price Chef needs to pay for the wireframe.

Constraints

• $1\le T\le 1000$
• $1 \leq N,M,X \leq 1000$

Explanation:

Test case $1$: The total length of the frame is $2\cdot 10 + 2\cdot 10 = 40$ cms. Since the cost is $10$ per cm, the total cost would be $10 \cdot 40 = 400$.

Test case $2$: The total length of the frame is $2\cdot 23 + 2\cdot 3 = 52$ cms. Since the cost is $12$ per cm, the total cost would be $52 \cdot 12 = 624$.

Test case $3$: The total length of the frame is $2\cdot 1000 + 2\cdot 1000 = 4000$ cms. Since the cost is $1000$ per cm, the total cost would be $4000 \cdot 1000 = 4000000$.

INPUT

3 10 10 10 23 3 12 1000 1000 1000

OUTPUT

400 624 4000000

/* package codechef; // don't place package name! */ import java.util.*; import java.lang.*; import java.io.*; /* Name of the class has to be "Main" only if the class is public. */ class Codechef { public static void main (String[] args) throws java.lang.Exception { try{ Scanner sc = new Scanner(System.in); int t= sc.nextInt(); while(t>=1 && t<=1000) { int n = sc.nextInt(); int m = sc.nextInt(); int x = sc.nextInt(); int tlength = 0,cost=0; if(n>=1 && n<=1000 && m>=1 && m<=1000 && x>=1 && x<=1000) { tlength = n * 2 + m * 2; cost = x * tlength; System.out.println(cost); } } } catch(Exception e){ return; } } }